Formula:KLS:01.05:10

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n = - 1 Γ ( n + c ) Γ ( n + d ) Γ ( 1 - a - n ) Γ ( 1 - b - n ) = Γ ( c + d - a - b - 1 ) Γ ( c - a ) Γ ( d - a ) Γ ( c - b ) Γ ( d - b ) superscript subscript 𝑛 1 Euler-Gamma 𝑛 𝑐 Euler-Gamma 𝑛 𝑑 Euler-Gamma 1 𝑎 𝑛 Euler-Gamma 1 𝑏 𝑛 Euler-Gamma 𝑐 𝑑 𝑎 𝑏 1 Euler-Gamma 𝑐 𝑎 Euler-Gamma 𝑑 𝑎 Euler-Gamma 𝑐 𝑏 Euler-Gamma 𝑑 𝑏 {\displaystyle{\displaystyle{\displaystyle\sum_{n=-\infty}^{\infty}\frac{1}{% \Gamma\left(n+c\right)\Gamma\left(n+d\right)\Gamma\left(1-a-n\right)\Gamma% \left(1-b-n\right)}{}=\frac{\Gamma\left(c+d-a-b-1\right)}{\Gamma\left(c-a% \right)\Gamma\left(d-a\right)\Gamma\left(c-b\right)\Gamma\left(d-b\right)}}}}

Proof

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Symbols List

Σ Σ {\displaystyle{\displaystyle{\displaystyle\Sigma}}}  : sum : http://drmf.wmflabs.org/wiki/Definition:sum
Γ Γ {\displaystyle{\displaystyle{\displaystyle\Gamma}}}  : Euler's gamma function : http://dlmf.nist.gov/5.2#E1

Bibliography

Equation in Section 1.5 of KLS.

URL links

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