DLMF:17.2.E36 (Q5326)

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DLMF:17.2.E36
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    j = 0 n ( n j ) ( - z ) j = ( 1 - z ) n . superscript subscript 𝑗 0 𝑛 binomial 𝑛 𝑗 superscript 𝑧 𝑗 superscript 1 𝑧 𝑛 {\displaystyle{\displaystyle\sum_{j=0}^{n}\genfrac{(}{)}{0.0pt}{}{n}{j}(-z)^{j% }=(1-z)^{n}.}}
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    DLMF:17.2.E36
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