DLMF:25.6.E17 (Q7654)

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DLMF:25.6.E17
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    ( n + 3 4 ) ζ ( 4 n + 2 ) = k = 1 n ζ ( 2 k ) ζ ( 4 n + 2 - 2 k ) , 𝑛 3 4 Riemann-zeta 4 𝑛 2 superscript subscript 𝑘 1 𝑛 Riemann-zeta 2 𝑘 Riemann-zeta 4 𝑛 2 2 𝑘 {\displaystyle{\displaystyle\left(n+\tfrac{3}{4}\right)\zeta\left(4n+2\right)=% \sum_{k=1}^{n}\zeta\left(2k\right)\zeta\left(4n+2-2k\right),}}
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    DLMF:25.6.E17
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    n 1 𝑛 1 {\displaystyle{\displaystyle n\geq 1}}
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