DLMF:3.4#Ex2 (Q1188)

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DLMF:3.4#Ex2
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    B 0 3 = - 1 2 ( 1 + 4 t - 3 t 2 ) , superscript subscript 𝐵 0 3 1 2 1 4 𝑡 3 superscript 𝑡 2 {\displaystyle{\displaystyle B_{0}^{3}=-\tfrac{1}{2}(1+4t-3t^{2}),}}
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    DLMF:3.4#Ex2
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    Warning: Falling back to standard tex;
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