DLMF:6.15.E4 (Q2309)

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DLMF:6.15.E4
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    n = 1 ( - 1 ) n si ( 2 π n ) n = π ( 3 2 ln 2 - 1 ) . superscript subscript 𝑛 1 superscript 1 𝑛 shifted-sine-integral 2 𝜋 𝑛 𝑛 𝜋 3 2 2 1 {\displaystyle{\displaystyle\sum_{n=1}^{\infty}(-1)^{n}\frac{\mathrm{si}\left(% 2\pi n\right)}{n}=\pi(\tfrac{3}{2}\ln 2-1).}}
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    DLMF:6.15.E4
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