DLMF:3.3#Ex19 (Q1143)

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DLMF:3.3#Ex19
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    A 0 5 = - 1 12 ( t 2 - 1 ) ( t 2 - 4 ) ( t - 3 ) , superscript subscript 𝐴 0 5 1 12 superscript 𝑡 2 1 superscript 𝑡 2 4 𝑡 3 {\displaystyle{\displaystyle A_{0}^{5}=-\tfrac{1}{12}(t^{2}-1)(t^{2}-4)(t-3),}}
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    DLMF:3.3#Ex19
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