DLMF:3.3#Ex22 (Q1146)

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DLMF:3.3#Ex22
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    A 3 5 = 1 120 t ( t 2 - 1 ) ( t 2 - 4 ) , superscript subscript 𝐴 3 5 1 120 𝑡 superscript 𝑡 2 1 superscript 𝑡 2 4 {\displaystyle{\displaystyle A_{3}^{5}=\tfrac{1}{120}t(t^{2}-1)(t^{2}-4),}}
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    DLMF:3.3#Ex22
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