DLMF:3.4#Ex1 (Q1187)

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DLMF:3.4#Ex1
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    B - 1 3 = - 1 6 ( 2 - 6 t + 3 t 2 ) , superscript subscript 𝐵 1 3 1 6 2 6 𝑡 3 superscript 𝑡 2 {\displaystyle{\displaystyle B_{-1}^{3}=-\tfrac{1}{6}(2-6t+3t^{2}),}}
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    DLMF:3.4#Ex1
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