DLMF:26.15.E8 (Q7975)

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DLMF:26.15.E8
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    N 0 ( B ) N ( 0 , B ) = k = 0 n ( - 1 ) k r k ( B ) ( n - k ) ! . equal-by definition subscript 𝑁 0 𝐵 𝑁 0 𝐵 superscript subscript 𝑘 0 𝑛 superscript 1 𝑘 subscript 𝑟 𝑘 𝐵 𝑛 𝑘 {\displaystyle{\displaystyle N_{0}(B)\equiv N(0,B)=\sum_{k=0}^{n}(-1)^{k}r_{k}% (B)(n-k)!.}}
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    DLMF:26.15.E8
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