DLMF:26.15.E8 (Q7975)

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DLMF:26.15.E8
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    N 0 ( B ) N ( 0 , B ) = k = 0 n ( - 1 ) k r k ( B ) ( n - k ) ! . equal-by definition subscript 𝑁 0 𝐵 𝑁 0 𝐵 superscript subscript 𝑘 0 𝑛 superscript 1 𝑘 subscript 𝑟 𝑘 𝐵 𝑛 𝑘 {\displaystyle{\displaystyle N_{0}(B)\equiv N(0,B)=\sum_{k=0}^{n}(-1)^{k}r_{k}% (B)(n-k)!.}}
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    DLMF:26.15.E8
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    equal-by definition {\displaystyle{\displaystyle\equiv}}
    introduction.Sx4.p1.t1.r9.m2adec
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    ! {\displaystyle{\displaystyle!}}
    introduction.Sx4.p1.t1.r15.m5aadec
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    k 𝑘 {\displaystyle{\displaystyle k}}
    C26.S1.XMD4.m1ddec
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    n 𝑛 {\displaystyle{\displaystyle n}}
    C26.S1.XMD6.m1cdec
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    B 𝐵 {\displaystyle{\displaystyle B}}
    C26.S15.XMD2.m1edec
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    r j ( B ) subscript 𝑟 𝑗 𝐵 {\displaystyle{\displaystyle r_{j}(B)}}
    C26.S15.XMD3.m1bdec
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    N ( x , B ) 𝑁 𝑥 𝐵 {\displaystyle{\displaystyle N(x,B)}}
    C26.S15.XMD6.m1bdec
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