DLMF:1.6.E12 (Q189)

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DLMF:1.6.E12
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    a j b j = j = 1 3 a j b j = 𝐚 𝐛 . subscript 𝑎 𝑗 subscript 𝑏 𝑗 superscript subscript 𝑗 1 3 subscript 𝑎 𝑗 subscript 𝑏 𝑗 𝐚 𝐛 {\displaystyle{\displaystyle a_{j}b_{j}=\sum_{j=1}^{3}a_{j}b_{j}=\mathbf{a}% \cdot\mathbf{b}.}}
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    DLMF:1.6.E12
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    Warning: Falling back to standard tex;
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    j 𝑗 {\displaystyle{\displaystyle j}}
    C1.S1.XMD3.m1dec
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