DLMF:19.11#Ex1 (Q6273)

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DLMF:19.11#Ex1
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    sin ψ = ( sin θ cos ϕ ) Δ ( ϕ ) + ( sin ϕ cos θ ) Δ ( θ ) 1 - k 2 sin 2 θ sin 2 ϕ , 𝜓 𝜃 italic-ϕ Δ italic-ϕ italic-ϕ 𝜃 Δ 𝜃 1 superscript 𝑘 2 2 𝜃 2 italic-ϕ {\displaystyle{\displaystyle\sin\psi=\frac{(\sin\theta\cos\phi)\Delta(\phi)+(% \sin\phi\cos\theta)\Delta(\theta)}{1-k^{2}{\sin^{2}}\theta{\sin^{2}}\phi},}}
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    DLMF:19.11#Ex1
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